Two pendulums have time periods T and 5T/4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation?

Question

Two pendulums have time periods T and 5T/4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation? (A)  45°  (B)  90°  (C)  60°  (D)  30°

Tardigrade Admin · Accepted Answer

When bigger pendulum of time period (5T/4) completes one vibration, the smaller pendulum will complete (5/4) vibrations. It means the smaller pendulum will be leading the bigger pendulum by phase T/4 second =π /2 rad =90°

Q. Two pendulums have time periods $T$ and $5 T /4$ . They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation?

$4 5^{\circ}$

$9 0^{\circ}$

$6 0^{\circ}$

$3 0^{\circ}$

When bigger pendulum of time period $(5 T /4)$ completes one vibration, the smaller pendulum will complete $(5/4)$ vibrations. It means the smaller pendulum will be leading the bigger pendulum by phase $T /4$ second
$= π /2$ rad $= 9 0^{\circ}$

Q. Two pendulums have time periods T and 5T/4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation?

45∘

90∘

60∘

30∘