Two particles of mass 1 kg and 3 kg move towards each other under their mutual force of attraction. No other force acts on them. When the relative velocity of approach of two particles is 2 m s- 1 , their centre of mass has a velocity of 0.5 m s- 1 . When the relative velocity of approach becomes 3 m s- 1 , the velocity of the centre of mass will be

Question

Two particles of mass 1 kg and 3 kg move towards each other under their mutual force of attraction. No other force acts on them. When the relative velocity of approach of two particles is 2 m s- 1 , their centre of mass has a velocity of 0.5 m s- 1 . When the relative velocity of approach becomes 3 m s- 1 , the velocity of the centre of mass will be (A) 0.75ms- 1 (B) 0.5ms- 1 (C) 10ms- 1 (D) 1.25ms- 1

Tardigrade Admin · Accepted Answer

Net external force on the system is zero. So, the velocity of the centre of mass will remain constant, i.e., 0.5ms- 1 .

$0.75 m s^{- 1}$

$0.5 m s^{- 1}$

$10 m s^{- 1}$

$1.25 m s^{- 1}$

Net external force on the system is zero. So, the velocity of the centre of mass will remain constant, i.e., $0.5 m s^{- 1}$ .

0.75ms−1

0.5ms−1

10ms−1

1.25ms−1

Net external force on the system is zero. So, the velocity of the centre of mass will remain constant, i.e., 0.5ms−1 .

$0.75 m s^{- 1}$

$0.5 m s^{- 1}$

$10 m s^{- 1}$

$1.25 m s^{- 1}$

Net external force on the system is zero. So, the velocity of the centre of mass will remain constant, i.e., $0.5 m s^{- 1}$ .