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  4. Two particles of mass 1 kg and 3 kg move towards each other under their mutual force of attraction. No other force acts on them. When the relative velocity of approach of two particles is 2 m s- 1 , their centre of mass has a velocity of 0.5 m s- 1 . When the relative velocity of approach becomes 3 m s- 1 , the velocity of the centre of mass will be

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Q. Two particles of mass $1 \, kg$ and $3 \, kg$ move towards each other under their mutual force of attraction. No other force acts on them. When the relative velocity of approach of two particles is $2 \, m \, s^{- 1}$ , their centre of mass has a velocity of $0.5 \, m \, s^{- 1}$ . When the relative velocity of approach becomes $3 \, m \, s^{- 1}$ , the velocity of the centre of mass will be

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Solution:

Net external force on the system is zero. So, the velocity of the centre of mass will remain constant, i.e., $0.5ms^{- 1}$ .