Two particles of equal mass ' m ' move in a circle of radius ' r ' under the action of their mutual gravitational attraction. The speed of each particle will be :

Question

Two particles of equal mass ' m ' move in a circle of radius ' r ' under the action of their mutual gravitational attraction. The speed of each particle will be : (A) √(G m/r) (B) √(G m/4 r) (C) √(4 G m/r) (D) √(G m/2 r)

Tardigrade Admin · Accepted Answer

Correct answer is (b) √(G m/4 r)

Q. Two particles of equal mass ' $m$ ' move in a circle of radius ' $r$ ' under the action of their mutual gravitational attraction. The speed of each particle will be :

$\frac{G m}{r}$

$\frac{G m}{4 r}$

$\frac{4 G m}{r}$

$\frac{G m}{2 r}$

Correct answer is (b) $\frac{G m}{4 r}$

Q. Two particles of equal mass ' m ' move in a circle of radius ' r ' under the action of their mutual gravitational attraction. The speed of each particle will be :

rGm​​

4rGm​​

r4Gm​​

2rGm​​