Two particles having masses 4 g and 16 g respectively are moving with equal kinetic energies. The ratio of the magnitudes of their linear momentum is n: 2. The value of n will be.

Question

Two particles having masses 4 g and 16 g respectively are moving with equal kinetic energies. The ratio of the magnitudes of their linear momentum is n: 2. The value of n will be. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

( p 12/2 × 4)=( p 22/2 × 16) ( p 1/ p 2)=(1/2)

Q. Two particles having masses $4 g$ and $16 g$ respectively are moving with equal kinetic energies. The ratio of the magnitudes of their linear momentum is $n : 2$ . The value of $n$ will be______.

$\frac{p _{1}^{2}}{2 \times 4} = \frac{p _{2}^{2}}{2 \times 16}$
$\frac{p _{1}}{p _{2}} = \frac{1}{2}$

Q. Two particles having masses 4g and 16g respectively are moving with equal kinetic energies. The ratio of the magnitudes of their linear momentum is n:2. The value of n will be______.

2×4p12​​=2×16p22​​ p2​p1​​=21​

Q. Two particles having masses $4 g$ and $16 g$ respectively are moving with equal kinetic energies. The ratio of the magnitudes of their linear momentum is $n : 2$ . The value of $n$ will be______.

$\frac{p _{1}^{2}}{2 \times 4} = \frac{p _{2}^{2}}{2 \times 16}$
$\frac{p _{1}}{p _{2}} = \frac{1}{2}$