Two particles, each of mass m and carrying charges Q, are separated by some distance. If they are in equilibrium under mutual gravitational and electrostatic forces then Q / m (in C / kg ) is of the order of

Question

Two particles, each of mass m and carrying charges Q, are separated by some distance. If they are in equilibrium under mutual gravitational and electrostatic forces then Q / m (in C / kg ) is of the order of (A) 10-5 (B) 10-10 (C) 10-15 (D) 10-20

Tardigrade Admin · Accepted Answer

The attractive gravitational force =G (m2/r2) and the repulsive electrostatic force =k (Q2/r2). where r is the separation between two particles For equilibrium, (G m2/r2)=(k Q2/r2) or (Q/m)=√(G/k) =[(6.67 × 10-11/9 × 109)]1 / 2 ∼ 10-10

Q. Two particles, each of mass $m$ and carrying charges $Q$ , are separated by some distance. If they are in equilibrium under mutual gravitational and electrostatic forces then $Q / m$ (in $C / k g$ ) is of the order of

$1 0^{- 5}$

$1 0^{- 10}$

$1 0^{- 15}$

$1 0^{- 20}$

Q. Two particles, each of mass m and carrying charges Q, are separated by some distance. If they are in equilibrium under mutual gravitational and electrostatic forces then Q/m (in C/kg ) is of the order of

10−5

10−10

10−15

10−20

The attractive gravitational force =Gr2m2​ and the repulsive electrostatic force =kr2Q2​. where r is the separation between two particles For equilibrium, r2Gm2​=r2kQ2​ or mQ​=kG​​ =[9×1096.67×10−11​]1/2∼10−10

Q. Two particles, each of mass $m$ and carrying charges $Q$ , are separated by some distance. If they are in equilibrium under mutual gravitational and electrostatic forces then $Q / m$ (in $C / k g$ ) is of the order of

$1 0^{- 5}$

$1 0^{- 10}$

$1 0^{- 15}$

$1 0^{- 20}$