Two parallel plates of area A are separated by two different dielectrics as shown in figure. The net capacitance is

Question

Two parallel plates of area A are separated by two different dielectrics as shown in figure. The net capacitance is (A) (ε0 A/2 d) (B) (ε0 A/d) (C) (3 ε0 A/d) (D) (4 ε0 A/3 d)

Tardigrade Admin · Accepted Answer

The net capacitance C=(ε0 A/(d1)K1+(d2)K2 =(ε0 A/(d)2((1)1+(1/2))=(4 ε0 A/3 d)

Q. Two parallel plates of area A are separated by two different dielectrics as shown in figure. The net capacitance is

$\frac{ε _{0} A}{2 d}$

$\frac{ε _{0} A}{d}$

$\frac{3 ε _{0} A}{d}$

$\frac{4 ε _{0} A}{3 d}$

The net capacitance $C = \frac{ε _{0} A}{\frac{d _{1}}{K _{1}} + \frac{d _{2}}{K _{2}}}$
$= \frac{ε _{0} A}{\frac{d}{2} ( \frac{1}{1} + \frac{1}{2} )} = \frac{4 ε _{0} A}{3 d}$

Q. Two parallel plates of area A are separated by two different dielectrics as shown in figure. The net capacitance is

2dε0​A​

dε0​A​

d3ε0​A​

3d4ε0​A​

The net capacitance C=K1​d1​​+K2​d2​​ε0​A​ =2d​(11​+21​)ε0​A​=3d4ε0​A​

$\frac{ε _{0} A}{2 d}$

$\frac{ε _{0} A}{d}$

$\frac{3 ε _{0} A}{d}$

$\frac{4 ε _{0} A}{3 d}$

The net capacitance $C = \frac{ε _{0} A}{\frac{d _{1}}{K _{1}} + \frac{d _{2}}{K _{2}}}$
$= \frac{ε _{0} A}{\frac{d}{2} ( \frac{1}{1} + \frac{1}{2} )} = \frac{4 ε _{0} A}{3 d}$