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Q. Two parallel plates of area A are separated by two different dielectrics as shown in figure. The net capacitance isPhysics Question Image

ManipalManipal 2010Electrostatic Potential and Capacitance

Solution:

The net capacitance $C=\frac{\varepsilon_{0} A}{\frac{d_{1}}{K_{1}}+\frac{d_{2}}{K_{2}}}$
$=\frac{\varepsilon_{0} A}{\frac{d}{2}\left(\frac{1}{1}+\frac{1}{2}\right)}=\frac{4 \varepsilon_{0} A}{3 d}$