Two parallel large thin metal sheets have equal surface charge densities (σ=26.4 × 10-12 C / m 2) of opposite signs. The electric field between these sheets is

Question

Two parallel large thin metal sheets have equal surface charge densities (σ=26.4 × 10-12 C / m 2) of opposite signs. The electric field between these sheets is (A) 3 N / C (B) 1.5 × 10-10 N / C (C) 1.5 N / C (D) 3 × 10-10 N / C

Tardigrade Admin · Accepted Answer

The situation is shown in the figure. Plate 1 has surface charge density

σ

and plate 2 has surface charge density

- σ

. The electric fields at point

P

due to two charged plates add up, giving

E = E_{1} + E_{2} = \frac{σ}{2 ε _{0}} + \frac{σ}{2 ε _{0}} = \frac{σ}{ε _{0}}

Given,

σ = 26.4 \times 1 0^{- 12} C / m^{2}

ε_{0} = 8.85 \times 1 0^{- 12} C^{2} / N - m^{2}

Hence,

E = \frac{26.4 \times 1 0 ^{- 12}}{8.85 \times 1 0 ^{- 12}} \approx 3 N / C

Q. Two parallel large thin metal sheets have equal surface charge densities $(σ = 26.4 \times 1 0^{- 12} C / m^{2})$ of opposite signs. The electric field between these sheets is

$3 N / C$

$1.5 \times 1 0^{- 10} N / C$

$1.5 N / C$

$3 \times 1 0^{- 10} N / C$

Q. Two parallel large thin metal sheets have equal surface charge densities (σ=26.4×10−12C/m2) of opposite signs. The electric field between these sheets is

3N/C

1.5×10−10N/C

1.5N/C

3×10−10N/C

Q. Two parallel large thin metal sheets have equal surface charge densities $(σ = 26.4 \times 1 0^{- 12} C / m^{2})$ of opposite signs. The electric field between these sheets is

$3 N / C$

$1.5 \times 1 0^{- 10} N / C$

$1.5 N / C$

$3 \times 1 0^{- 10} N / C$