Two oxides of a metal contain 50 % and 40 % metal ( M ) respectively. If formula of first oxide is M O 2, the formula of second oxide will be

Question

Two oxides of a metal contain 50 % and 40 % metal ( M ) respectively. If formula of first oxide is M O 2, the formula of second oxide will be (A) M2 O 4 (B) M O 3 (C) M2 O (D) M2 O 5

Tardigrade Admin · Accepted Answer

First oxide is M O 2 containing 50 % of oxygen (32 g ) ∴ Metal contained is also 32 g Atomic mass of metal =( text Weight / text Number of moles )=(32/1)=32 Second oxide: Percentage Mole ratio Simple ratio M 40 (40/32)=1.25 1 O 60 (60/16)=3.75 3 Empirical formula = MO3

Q. Two oxides of a metal contain $50%$ and $40%$ metal ( $M$ ) respectively. If formula of first oxide is $M O_{2}$ , the formula of second oxide will be

$M_{2} O_{4}$

$M O_{3}$

$M_{2} O$

$M_{2} O_{5}$

Q. Two oxides of a metal contain 50% and 40% metal ( M ) respectively. If formula of first oxide is MO2​, the formula of second oxide will be

M2​O4​

MO3​

M2​O

M2​O5​

First oxide is MO2​ containing 50% of oxygen (32g) ∴ Metal contained is also 32g Atomic mass of metal = Number of moles Weight ​=132​=32 Second oxide: Percentage Mole ratio Simple ratio M 40 3240​=1.25 1 O 60 1660​=3.75 3 Empirical formula =MO3​

Q. Two oxides of a metal contain $50%$ and $40%$ metal ( $M$ ) respectively. If formula of first oxide is $M O_{2}$ , the formula of second oxide will be

$M_{2} O_{4}$

$M O_{3}$

$M_{2} O$

$M_{2} O_{5}$