Q.
Two opposite and equal charges 4×10−8 coulomb when placed 2×10−2cm away, form a dipole. If this dipole is placed in an external electric field 4×108 newton/ coulomb, the value of maximum torque and the work done in rotating it through 180∘ will be
2371
180
Electrostatic Potential and Capacitance
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Solution:
Dipole moment p=4×10−8×2×10−4 =8×10−12m
Maximum torque =pE=8×10−12×4×108 =32×10−4Nm
Work done in rotating through 180∘=2pE =2×32×10−4=64×10−4J