Two objects of mass 10 kg and 20 kg respectively are connected to the two ends of a rigid rod of length 10 m with negligible mass. The distance of the center of mass of the system from the 10 kg mass is :

Question

Two objects of mass 10 kg and 20 kg respectively are connected to the two ends of a rigid rod of length 10 m with negligible mass. The distance of the center of mass of the system from the 10 kg mass is : (A) 5 m (B) (10/3) m (C) (20/3) m (D) 10 m

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/77431dcc11441a6d0691a9bd444109e4-.png" /> X CM =(20 × 10/20+10)=(20/3) m

Q. Two objects of mass $10 k g$ and $20 k g$ respectively are connected to the two ends of a rigid rod of length $10 m$ with negligible mass. The distance of the center of mass of the system from the $10 k g$ mass is :

$5 m$

$\frac{10}{3} m$

$\frac{20}{3} m$

$10 m$

$X_{CM} = \frac{20 \times 10}{20 + 10} = \frac{20}{3} m$

Q. Two objects of mass 10kg and 20kg respectively are connected to the two ends of a rigid rod of length 10m with negligible mass. The distance of the center of mass of the system from the 10kg mass is :

5m

310​m

320​m

10m