Two numbers are selected randomly from the set S = 1, 2, 3, 4, 5, 6 without replacement. The probability that minimum of the two numbers is less than 4, is

Question

Two numbers are selected randomly from the set S = 1, 2, 3, 4, 5, 6 without replacement. The probability that minimum of the two numbers is less than 4, is (A) (1/15) (B) (14/15) (C) (1/5) (D) (4/5)

Tardigrade Admin · Accepted Answer

Here, two numbers are selected from 1,2,3,4,5,6 ⇒ n(S)=6 × 5 as one by one without replacement Favourable events = the minimum of the two numbers is less than 4 . n(E)=6 × 4 as for the minimum of the two is less than 4 we can select one from (1,2,3,4) and other from (1,2,3, 4,5,6) ∴ Required probability =(n(E)/n(S))=(24/30)=(4/5)

Q. Two numbers are selected randomly from the set $S = {1, 2, 3, 4, 5, 6}$ without replacement. The probability that minimum of the two numbers is less than $4$ , is

$\frac{1}{15}$

$\frac{14}{15}$

$\frac{1}{5}$

$\frac{4}{5}$

Q. Two numbers are selected randomly from the set S={1,2,3,4,5,6} without replacement. The probability that minimum of the two numbers is less than 4, is

151​

1514​

51​

54​

Q. Two numbers are selected randomly from the set $S = {1, 2, 3, 4, 5, 6}$ without replacement. The probability that minimum of the two numbers is less than $4$ , is

$\frac{1}{15}$

$\frac{14}{15}$

$\frac{1}{5}$

$\frac{4}{5}$