Two monomers in maltose are

Question

Two monomers in maltose are (A) α -D-glucose and α -D-Fructose (B) α -D-glucose and β -D-galactose (C) α -D-glucose and α -D-glucose (D) α -D-glucose and α -D-galactose

Tardigrade Admin · Accepted Answer

Maltose on hydrolysis give 2 mole of α -D Glucose because in maltose glucosidic linkage is present in between C1 C4 of α -D glucose. <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-opmabsx1i44l.png" />

Q. Two monomers in maltose are

$α$ -D-glucose and $α$ -D-Fructose

$α$ -D-glucose and $β$ -D-galactose

$α$ -D-glucose and $α$ -D-glucose

$α$ -D-glucose and $α$ -D-galactose

Maltose on hydrolysis give 2 mole of $α$ -D Glucose because in maltose glucosidic linkage is present in between $C_{1}$ & $C_{4}$ of $α$ -D glucose.

Q. Two monomers in maltose are

α -D-glucose and α -D-Fructose

α -D-glucose and β -D-galactose

α -D-glucose and α -D-glucose

α -D-glucose and α -D-galactose

Maltose on hydrolysis give 2 mole of α -D Glucose because in maltose glucosidic linkage is present in between C1​ & C4​ of α -D glucose.

$α$ -D-glucose and $α$ -D-Fructose

$α$ -D-glucose and $β$ -D-galactose

$α$ -D-glucose and $α$ -D-glucose

$α$ -D-glucose and $α$ -D-galactose

Maltose on hydrolysis give 2 mole of $α$ -D Glucose because in maltose glucosidic linkage is present in between $C_{1}$ & $C_{4}$ of $α$ -D glucose.