Two moles of NH3 when put into a previously evacuated vessel (one litre) partially dissociate into N2 and H2. If at equilibrium one mole of NH3 is present, the equilibrium constant is

Question

Two moles of NH3 when put into a previously evacuated vessel (one litre) partially dissociate into N2 and H2. If at equilibrium one mole of NH3 is present, the equilibrium constant is (A) 3/4 mol2 litre-2 (B) 27/64 mol2 litre-2 (C) 27/32 mol2 litre-2 (D) 27/1 mol2 litre-2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/60a5ba24aaf74ea53d13a38d14302fc0-.png" /> K= ([N2][H2]3/[NH3]2) = (1×33/1) =27

Q. Two moles of $N H_{3}$ when put into a previously evacuated vessel (one litre) partially dissociate into $N_{2}$ and $H_{2}$ . If at equilibrium one mole of $N H_{3}$ is present, the equilibrium constant is

$3/4 m o l^{2} l i t r e^{- 2}$

$27/64 m o l^{2} l i t r e^{- 2}$

$27/32 m o l^{2} l i t r e^{- 2}$

$27/1 m o l^{2} l i t r e^{- 2}$

$K = \frac{[ N _{2} ] [ H _{2} ] ^{3}}{[ N H _{3} ] ^{2}} = \frac{1 \times 3 ^{3}}{1} = 27$

Q. Two moles of NH3​ when put into a previously evacuated vessel (one litre) partially dissociate into N2​ and H2​. If at equilibrium one mole of NH3​ is present, the equilibrium constant is

3/4mol2litre−2

27/64mol2litre−2

27/32mol2litre−2

27/1mol2litre−2