Question

Two moles of $NH_{3}$ when put into a previously evacuated vessel (one litre) partially dissociate into $N_{2}$ and $H_{2}$. If at equilibrium one mole of $NH_{3}$ is present, the equilibrium constant is

• A. $3/4 \,mol^{2}\, litre^{-2}$
• B. $27/64\, mol^{2} \,litre^{-2}$
• C. $27/32\, mol^{2} \,litre^{-2}$
• D. $27/1\, mol^{2}\, litre^{-2}$

Answer 1

Answer: (D)

$K= \frac {[N_{2}][H_{2}]^{3}}{[NH_{3}]^{2}} = \frac {1\times3^{3}}{1} =27$