Two moles of an ideal monoatomic gas undergo a cyclic process as shown in the figure. The temperatures in different states are given as 6 T1=3 T2=2 T4=T3=1800 K. Determine the work done by the gas during the cycle.

Question

Two moles of an ideal monoatomic gas undergo a cyclic process as shown in the figure. The temperatures in different states are given as 6 T1=3 T2=2 T4=T3=1800 K. Determine the work done by the gas during the cycle. (A) -1200 R (B) 1200 R (C) 1575 R (D) -800 R

Tardigrade Admin · Accepted Answer

6 T1=3 T2=2 T4=T3=1800 K T1=300 K , T2=600 K T4=900 K , T3=1800 K 1 arrow 4 and 2 arrow 3 are isochoric process work done =0 W12 =P(V2-V1)=n R(T2-T1) =2 × R(600-300)=600 R W341 =P(V4-V3)=n R(T4-T3) =2 × R(900-1800)=-1800 R W text total =600 R-1800 R=-1200 R

Q. Two moles of an ideal monoatomic gas undergo a cyclic process as shown in the figure. The temperatures in different states are given as 6T1​=3T2​=2T4​=T3​=1800 K. Determine the work done by the gas during the cycle.

-1200 R

1200 R

1575 R

-800 R

6T1​=3T2​=2T4​=T3​=1800K T1​=300K,T2​=600K T4​=900K,T3​=1800K 1→4 and 2→3 are isochoric process work done =0 W12​=P(V2​−V1​)=nR(T2​−T1​) =2×R(600−300)=600R W341​=P(V4​−V3​)=nR(T4​−T3​) =2×R(900−1800)=−1800R Wtotal ​=600R−1800R=−1200R

Q. Two moles of an ideal monoatomic gas undergo a cyclic process as shown in the figure. The temperatures in different states are given as $6 T_{1} = 3 T_{2} = 2 T_{4} = T_{3} = 1800$ K. Determine the work done by the gas during the cycle.