Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Two moles of an ideal gas is expanded isothermally and reversibly from 5 to 1 bar at 298 K . The change in entropy (in JK-1) of the system is
Q. Two moles of an ideal gas is expanded isothermally and reversibly from
5
to
1
bar at
298
K
. The change in entropy (in
J
K
−
1
)
of the system is
1666
224
Thermodynamics
Report Error
A
13.38
J
K
−
1
B
26.77
J
K
−
1
C
zero
D
16.82
J
K
−
1
Solution:
The entropy change during isothermal reversible expansion,
Δ
S
=
n
R
ln
p
2
p
1
=
2
×
8.314
×
l
n
(
1
5
)
=
2
×
8.314
×
1.61
=
26.77
J
K
−
1