Two metallic concentric shells are shown. Before closing the switch charge on inner shell is Q and charge on outer shell is 2 Q. Potential at point ' A' is V. What will be potential at same point after closing the switch :-

Question

Two metallic concentric shells are shown. Before closing the switch charge on inner shell is Q and charge on outer shell is 2 Q. Potential at point ' A' is V. What will be potential at same point after closing the switch :- (A) V (B) 2 V (C) (3/4) V (D) (2/3) V

Tardigrade Admin · Accepted Answer

V A =( kQ / a )+( k (2 Q )/2 a )=2 ( kQ / a )= V V A 1=( k ( Q +2 Q )/2 a )=(3 kQ /2 a )=(3/2) × ( V /2)=(3 V /4)

Q. Two metallic concentric shells are shown. Before closing the switch charge on inner shell is $Q$ and charge on outer shell is $2 Q$ . Potential at point ' $A$ ' is $V$ . What will be potential at same point after closing the switch :-

$V$

$2 V$

$\frac{3}{4} V$

$\frac{2}{3} V$

$V_{A} = \frac{k Q}{a} + \frac{k ( 2 Q )}{2 a} = 2 \frac{k Q}{a} = V$
$V_{A}^{1} = \frac{k ( Q + 2 Q )}{2 a} = \frac{3 k Q}{2 a} = \frac{3}{2} \times \frac{V}{2} = \frac{3 V}{4}$

Q. Two metallic concentric shells are shown. Before closing the switch charge on inner shell is Q and charge on outer shell is 2Q. Potential at point ' A' is V. What will be potential at same point after closing the switch :-

V

2V

43​V

32​V

VA​=akQ​+2ak(2Q)​=2akQ​=V VA1​=2ak(Q+2Q)​=2a3kQ​=23​×2V​=43V​

Q. Two metallic concentric shells are shown. Before closing the switch charge on inner shell is $Q$ and charge on outer shell is $2 Q$ . Potential at point ' $A$ ' is $V$ . What will be potential at same point after closing the switch :-

$V$

$2 V$

$\frac{3}{4} V$

$\frac{2}{3} V$

$V_{A} = \frac{k Q}{a} + \frac{k ( 2 Q )}{2 a} = 2 \frac{k Q}{a} = V$
$V_{A}^{1} = \frac{k ( Q + 2 Q )}{2 a} = \frac{3 k Q}{2 a} = \frac{3}{2} \times \frac{V}{2} = \frac{3 V}{4}$