Two metal plates are separated by 2 cm. The potentials of the plates are − 10 V and + 30 V. The electric field between the two plates is

Question

Two metal plates are separated by 2 cm. The potentials of the plates are − 10 V and + 30 V. The electric field between the two plates is (A) 2000 V/m (B) 500 V/m (C) 3000 V/m (D) 1000 V/m

Tardigrade Admin · Accepted Answer

E=(V/α)=(30-(-10)/2×10-2)=2000 V m-1 (α=distance between two plates)

Q. Two metal plates are separated by 2 cm. The potentials of the plates are − 10 V and + 30 V. The electric field between the two plates is

2000 V/m

500 V/m

3000 V/m

1000 V/m

$E = \frac{V}{α} = \frac{30 - ( - 10 )}{2 \times 1 0 ^{- 2}} = 2000 V m^{- 1} (α = d i s t an ce b e tw ee n tw o pl a t es)$

Q. Two metal plates are separated by 2 cm. The potentials of the plates are − 10 V and + 30 V. The electric field between the two plates is

2000 V/m

500 V/m

3000 V/m

1000 V/m

E=αV​=2×10−230−(−10)​=2000Vm−1(α=distancebetweentwoplates)

$E = \frac{V}{α} = \frac{30 - ( - 10 )}{2 \times 1 0 ^{- 2}} = 2000 V m^{- 1} (α = d i s t an ce b e tw ee n tw o pl a t es)$