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  4. Two metal plates are separated by 2 cm. The potentials of the plates are − 10 V and + 30 V. The electric field between the two plates is

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Q. Two metal plates are separated by 2 cm. The potentials of the plates are − 10 V and + 30 V. The electric field between the two plates is

KCETKCET 2019Electrostatic Potential and Capacitance

Solution:

$\quad E=\frac{V}{\alpha}=\frac{30-\left(-10\right)}{2\times10^{-2}}=2000 V m^{-1}\quad\left(\alpha=distance\, between \,two\, plates\right)\quad$