Two materials of dielectric constant k1 and k2 are filled between two parallel plates of a capacitor as shown in fig. The capacities of capacitor is :

Question

Two materials of dielectric constant k1 and k2 are filled between two parallel plates of a capacitor as shown in fig. The capacities of capacitor is : (A)  (2Aε o/d)( (k1k2/k1+k2) )  (B)  (Aε o/d)( (k1k2/k1+k2) )  (C)  (2Aε 0(k1+k2)/d)  (D)  (Aε 0(k1+k2)/d)

Tardigrade Admin · Accepted Answer

Capacitance of the first capacitor C1=(ε 0AK1/d) Capacitance of the second capacitor C2=(ε 0AK2/d) As the two capacitors are connected in a parallel combination. Therefore, the net capacity will be C=C1+C2=(ε 0K1A/d)+(ε 0K2A/d) =(Aε 0/d)(K1+K2)

Q. Two materials of dielectric constant $k_{1}$ and $k_{2}$ are filled between two parallel plates of a capacitor as shown in fig. The capacities of capacitor is :

$\frac{2 A ε _{o}}{d} (\frac{k _{1} k _{2}}{k _{1} + k _{2}})$

$\frac{A ε _{o}}{d} (\frac{k _{1} k _{2}}{k _{1} + k _{2}})$

$\frac{2 A ε _{0} ( k _{1} + k _{2} )}{d}$

$\frac{A ε _{0} ( k _{1} + k _{2} )}{d}$

Q. Two materials of dielectric constant k1​ and k2​ are filled between two parallel plates of a capacitor as shown in fig. The capacities of capacitor is :

d2Aεo​​(k1​+k2​k1​k2​​)

dAεo​​(k1​+k2​k1​k2​​)

d2Aε0​(k1​+k2​)​

dAε0​(k1​+k2​)​

Capacitance of the first capacitor C1​=dε0​AK1​​ Capacitance of the second capacitor C2​=dε0​AK2​​ As the two capacitors are connected in a parallel combination. Therefore, the net capacity will be C=C1​+C2​=dε0​K1​A​+dε0​K2​A​ =dAε0​​(K1​+K2​)

Q. Two materials of dielectric constant $k_{1}$ and $k_{2}$ are filled between two parallel plates of a capacitor as shown in fig. The capacities of capacitor is :

$\frac{2 A ε _{o}}{d} (\frac{k _{1} k _{2}}{k _{1} + k _{2}})$

$\frac{A ε _{o}}{d} (\frac{k _{1} k _{2}}{k _{1} + k _{2}})$

$\frac{2 A ε _{0} ( k _{1} + k _{2} )}{d}$

$\frac{A ε _{0} ( k _{1} + k _{2} )}{d}$