Two masses A and B of 10kg and 5kg respectively, are connected with a string passing over a frictionless pulley fixed at the corner of a table as shown in the figure. The coefficient of friction of A with the table is 0.2 , the minimum mass of C that may be placed on A to prevent it from moving is

Question

Two masses A and B of 10kg and 5kg respectively, are connected with a string passing over a frictionless pulley fixed at the corner of a table as shown in the figure. The coefficient of friction of A with the table is 0.2 , the minimum mass of C that may be placed on A to prevent it from moving is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-xtffionf1vemjc6s.jpg" /> (A) 15kg (B) 5kg (C) 10kg (D) 0kg

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-xtffionf1vemrkrf.jpg" /> Since the given system is in equilibrium, therefore, tension in the string is 5g. When we consider the combination of A and C, then T=μ R or T=0.2 [10 + m a s s o f C]g or 5g=0.2 [10 + m a s s o f C]g Or mass of C=15kg

$15 k g$

$5 k g$

$10 k g$

$0 k g$

Since the given system is in equilibrium, therefore, tension in the string is 5g.
When we consider the combination of A and C, then
$T = μ R$
$or T = 0.2 [10 + ma ss o f C] g$
$or 5 g = 0.2 [10 + ma ss o f C] g$
Or mass of $C = 15 k g$

15kg

5kg

10kg

0kg

Since the given system is in equilibrium, therefore, tension in the string is 5g. When we consider the combination of A and C, then T=μR orT=0.2[10+massofC]g or5g=0.2[10+massofC]g Or mass of C=15kg

$15 k g$

$5 k g$

$10 k g$

$0 k g$

Since the given system is in equilibrium, therefore, tension in the string is 5g.
When we consider the combination of A and C, then
$T = μ R$
$or T = 0.2 [10 + ma ss o f C] g$
$or 5 g = 0.2 [10 + ma ss o f C] g$
Or mass of $C = 15 k g$