Two masses A and B, each of mass M are fixed together by a massless spring. A force acts on the mass B as shown in figure. If the mass A starts moving away from mass B with acceleration 'a' , then the acceleration of mass B wil be :-

Question

Two masses A and B, each of mass M are fixed together by a massless spring. A force acts on the mass B as shown in figure. If the mass A starts moving away from mass B with acceleration 'a' , then the acceleration of mass B wil be :- <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/bdf80c43c6b3b2b6e43e1c0b401fd8b4-.png" /> (A) ( Ma - F / M ) (B) ( MF / F + Ma ) (C) ( F + Ma / M ) (D) ( F - Ma / M )

Tardigrade Admin · Accepted Answer

a cm =( m 1 a 1+ m 2 a 2/ m 1+ m 2) ( F /2 M )=( Ma + Ma B /2 M ) a B =( F - Ma / M )

Q. Two masses $A$ and $B$ , each of mass $M$ are fixed together by a massless spring. $A$ force acts on the mass $B$ as shown in figure. If the mass $A$ starts moving away from mass $B$ with acceleration $^{'} a^{'}$ , then the acceleration of mass $B$ wil be :-

$\frac{M a - F}{M}$

$\frac{MF}{F + M a}$

$\frac{F + M a}{M}$

$\frac{F - M a}{M}$

$a_{c m} = \frac{m _{1} a _{1} + m _{2} a _{2}}{m _{1} + m _{2}}$
$\frac{F}{2 M} = \frac{M a + M a _{B}}{2 M}$
$a_{B} = \frac{F - M a}{M}$

Q. Two masses A and B, each of mass M are fixed together by a massless spring. A force acts on the mass B as shown in figure. If the mass A starts moving away from mass B with acceleration ′a′ , then the acceleration of mass B wil be :-

MMa−F​

F+MaMF​

MF+Ma​

MF−Ma​