Two litres of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 litres. How much heat is absorbed?

Question

Two litres of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 litres. How much heat is absorbed? (A) 0 (B) 1 (C) 2 (D) 4

Tardigrade Admin · Accepted Answer

For isothermal irreversible change q =-W =Pex(Vf-Vi) For expansion of an ideal gas in vacuum, pex=0 q=-W=0 (10-2)=0(8)=0 ∴ q=0

Q. Two litres of an ideal gas at a pressure of $10 a t m$ expands isothermally into a vacuum until its total volume is $10$ litres. How much heat is absorbed?

$0$

$1$

$2$

$4$

For isothermal irreversible change
$q = - W = P_{e x} (V_{f} - V_{i})$
For expansion of an ideal gas in vacuum,
$p_{e x} = 0$
$q = - W = 0 (10 - 2) = 0 (8) = 0$
$∴ q = 0$

Q. Two litres of an ideal gas at a pressure of 10atm expands isothermally into a vacuum until its total volume is 10 litres. How much heat is absorbed?

0

1

2

4

For isothermal irreversible change q=−W=Pex​(Vf​−Vi​) For expansion of an ideal gas in vacuum, pex​=0 q=−W=0(10−2)=0(8)=0 ∴q=0

Q. Two litres of an ideal gas at a pressure of $10 a t m$ expands isothermally into a vacuum until its total volume is $10$ litres. How much heat is absorbed?

$0$

$1$

$2$

$4$

For isothermal irreversible change
$q = - W = P_{e x} (V_{f} - V_{i})$
For expansion of an ideal gas in vacuum,
$p_{e x} = 0$
$q = - W = 0 (10 - 2) = 0 (8) = 0$
$∴ q = 0$