Two liquids are at temperature 20°C and 40°C. When same mass of both of them is mixed, the temperature of the mixture is 32° C. What is the ratio of their specific heats ?

Question

Two liquids are at temperature 20°C and 40°C. When same mass of both of them is mixed, the temperature of the mixture is 32° C. What is the ratio of their specific heats ? (A) 1/3 (B) 2/3 (C) 1/5 (D) 2/5.

Tardigrade Admin · Accepted Answer

Mc1(32 - 20) = Mc2 (40 - 32) . This gives c1 / c2 = 2 /3.

Q. Two liquids are at temperature $2 0^{\circ}$ C and $4 0^{\circ}$ C. When same mass of both of them is mixed, the temperature of the mixture is $3 2^{\circ}$ C. What is the ratio of their specific heats ?

1/3

2/3

1/5

2/5.

$M c_{1} (32 - 20) = M c_{2} (40 - 32)$
. $T hi s g i v es c_{1} / c_{2} = 2/3.$

Q. Two liquids are at temperature 20∘C and 40∘C. When same mass of both of them is mixed, the temperature of the mixture is 32∘ C. What is the ratio of their specific heats ?

1/3

2/3

1/5

2/5.

Mc1​(32−20)=Mc2​(40−32) . Thisgivesc1​/c2​=2/3.

Q. Two liquids are at temperature $2 0^{\circ}$ C and $4 0^{\circ}$ C. When same mass of both of them is mixed, the temperature of the mixture is $3 2^{\circ}$ C. What is the ratio of their specific heats ?

$M c_{1} (32 - 20) = M c_{2} (40 - 32)$
. $T hi s g i v es c_{1} / c_{2} = 2/3.$