Two liquids A and B have pA°: pB°=1: 3 at a certain temperature. If the mole fraction ratio of xA: xB=1: 3, the mole fraction of A in vapor in equilibrium with the solution at a given temperature is

Question

Two liquids A and B have pA°: pB°=1: 3 at a certain temperature. If the mole fraction ratio of xA: xB=1: 3, the mole fraction of A in vapor in equilibrium with the solution at a given temperature is (A) 0.1 (B) 0.2 (C) 0.5 (D) 1.0

Tardigrade Admin · Accepted Answer

yA =(pA0 xA/pA° xA+pB° xB) =(1/1+(pB° xB)pA° xA) =(1/1+(3)(3))=(1/10)=0.1

Q. Two liquids $A$ and $B$ have $p_{A}^{\circ} : p_{B}^{\circ} = 1 : 3$ at a certain temperature. If the mole fraction ratio of $x_{A} : x_{B} = 1 : 3$ , the mole fraction of $A$ in vapor in equilibrium with the solution at a given temperature is

0.1

0.2

0.5

1.0

$y_{A} = \frac{p _{A}^{0} x _{A}}{p _{A}^{\circ} x _{A} + p _{B}^{\circ} x _{B}}$

$= \frac{1}{1 + \frac{p _{B}^{\circ} x _{B}}{p _{A}^{\circ} x _{A}}}$

$= \frac{1}{1 + ( 3 ) ( 3 )} = \frac{1}{10} = 0.1$

Q. Two liquids A and B have pA∘​:pB∘​=1:3 at a certain temperature. If the mole fraction ratio of xA​:xB​=1:3, the mole fraction of A in vapor in equilibrium with the solution at a given temperature is

0.1

0.2

0.5

1.0

yA​=pA∘​xA​+pB∘​xB​pA0​xA​​ =1+pA∘​xA​pB∘​xB​​1​ =1+(3)(3)1​=101​=0.1

Q. Two liquids $A$ and $B$ have $p_{A}^{\circ} : p_{B}^{\circ} = 1 : 3$ at a certain temperature. If the mole fraction ratio of $x_{A} : x_{B} = 1 : 3$ , the mole fraction of $A$ in vapor in equilibrium with the solution at a given temperature is

$y_{A} = \frac{p _{A}^{0} x _{A}}{p _{A}^{\circ} x _{A} + p _{B}^{\circ} x _{B}}$

$= \frac{1}{1 + \frac{p _{B}^{\circ} x _{B}}{p _{A}^{\circ} x _{A}}}$

$= \frac{1}{1 + ( 3 ) ( 3 )} = \frac{1}{10} = 0.1$