Two liquids A and B have P A °: P B °=1: 3 at a certain temperature. If the mole fraction ratio of xA: xB=1: 3, the mole fraction of A in vapour in equilibrium with the solution at a given temperature is(Give your answer after multiply by 10 )

Question

Two liquids A and B have P A °: P B °=1: 3 at a certain temperature. If the mole fraction ratio of xA: xB=1: 3, the mole fraction of A in vapour in equilibrium with the solution at a given temperature is(Give your answer after multiply by 10 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

y A =( P A ° X A / P A ° X A + P B ° X B ), y A =(1/1+( P B ° X B ) P A ° X A ) y A =(1/1+(3)(3))=(1/10)=0.1

Q. Two liquids $A$ and $B$ have $P_{A}^{\circ} : P_{B}^{\circ} = 1 : 3$ at a certain temperature. If the mole fraction ratio of $x_{A} : x_{B} = 1 : 3$ , the mole fraction of $A$ in vapour in equilibrium with the solution at a given temperature is(Give your answer after multiply by $10$ )

$y_{A} = \frac{P _{A}^{\circ} X _{A}}{P _{A}^{\circ} X _{A} + P _{B}^{\circ} X _{B}},$
$y_{A} = \frac{1}{1 + \frac{P _{B}^{\circ} X _{B}}{P _{A}^{\circ} X _{A}}}$
$y_{A} = \frac{1}{1 + ( 3 ) ( 3 )} = \frac{1}{10} = 0.1$

Q. Two liquids A and B have PA​∘:PB​∘=1:3 at a certain temperature. If the mole fraction ratio of xA​:xB​=1:3, the mole fraction of A in vapour in equilibrium with the solution at a given temperature is(Give your answer after multiply by 10 )

yA​=PA∘​XA​+PB∘​XB​PA∘​XA​​, yA​=1+PA∘​XA​PB∘​XB​​1​ yA​=1+(3)(3)1​=101​=0.1

Q. Two liquids $A$ and $B$ have $P_{A}^{\circ} : P_{B}^{\circ} = 1 : 3$ at a certain temperature. If the mole fraction ratio of $x_{A} : x_{B} = 1 : 3$ , the mole fraction of $A$ in vapour in equilibrium with the solution at a given temperature is(Give your answer after multiply by $10$ )

$y_{A} = \frac{P _{A}^{\circ} X _{A}}{P _{A}^{\circ} X _{A} + P _{B}^{\circ} X _{B}},$
$y_{A} = \frac{1}{1 + \frac{P _{B}^{\circ} X _{B}}{P _{A}^{\circ} X _{A}}}$
$y_{A} = \frac{1}{1 + ( 3 ) ( 3 )} = \frac{1}{10} = 0.1$