Two linear polarizers are crossed at an angle of 60°. The fraction of intensity of light transmitted by the pair is

Question

Two linear polarizers are crossed at an angle of 60°. The fraction of intensity of light transmitted by the pair is (A) (1/4) (B) (1/8) (C) (3/8) (D) (1/2)

Tardigrade Admin · Accepted Answer

If I0 is the intensity of light incident on the first polarizer, then the intensity which comes out of it is I1=I0 / 2. This is the intensity incident on the second polarizer which is crossed at an angle of 60°. Therefore, the intensity that comes out of this second polarizer is I2=I1 cos 2 60°=I0 / 8

Q. Two linear polarizers are crossed at an angle of $6 0^{\circ}$ . The fraction of intensity of light transmitted by the pair is

$\frac{1}{4}$

$\frac{1}{8}$

$\frac{3}{8}$

$\frac{1}{2}$

Q. Two linear polarizers are crossed at an angle of 60∘. The fraction of intensity of light transmitted by the pair is

41​

81​

83​

21​

Q. Two linear polarizers are crossed at an angle of $6 0^{\circ}$ . The fraction of intensity of light transmitted by the pair is

$\frac{1}{4}$

$\frac{1}{8}$

$\frac{3}{8}$

$\frac{1}{2}$