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Q.
Two linear polarizers are crossed at an angle of $60^{\circ}$. The fraction of intensity of light transmitted by the pair is
Wave Optics
Solution:
If $I_{0}$ is the intensity of light incident on the first polarizer, then the intensity which comes out of it is $I_{1}=I_{0} / 2$. This is the intensity incident on the second polarizer which is crossed at an angle of $60^{\circ}$. Therefore, the intensity that comes out of this second polarizer is $I_{2}=I_{1} \cos ^{2} 60^{\circ}=I_{0} / 8$