Question

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below :
${}_1^{2}X+{}_1^{2}X={}_2^{4}Y$
The binding energies per nucleon ${}_1^{2}X$ and ${}_2^{4}Y$ are $1.1MeV$ and $7.6MeV$ respectively. The energy released in this process is _______$MeV$.

Answer 1

Answer: 26

Energy released in the given process $=$ Binding energy of product - Binding energy of reactants
$=7.6\times 4-(1.1\times 2)\times 2$
$=30.4-4.4$
$=26MeV$