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  4. Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below: 12 X + 12 X = 24 Y The binding energies per nucleon 12 X and 24 Y are 1.1 MeV and 7.6 MeV respectively. The energy released in this process is MeV.

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Q. Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below :
${ }_1^2 X +{ }_1^2 X ={ }_2^4 Y$
The binding energies per nucleon ${ }_1^2 X$ and ${ }_2^4 Y$ are $1.1 \,MeV$ and $7.6\, MeV$ respectively. The energy released in this process is _______$ MeV$.

JEE MainJEE Main 2022Nuclei

Solution:

Energy released in the given process $=$ Binding energy of product - Binding energy of reactants
$=7.6 \times 4-(1.1 \times 2) \times 2$
$=30.4-4.4$
$ =26 \,MeV$