Two inflated balloons I and II (thin skin) having volume 600 mL and 1500 mL at 300 K are taken as shown in diagram. If maximum volume of inner and outer balloons are 800 mL and 1800 mL respectively then find the balloon which will burst first on gradual heating.

Question

Two inflated balloons I and II (thin skin) having volume 600 mL and 1500 mL at 300 K are taken as shown in diagram. If maximum volume of inner and outer balloons are 800 mL and 1800 mL respectively then find the balloon which will burst first on gradual heating. <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-rujpumof10v8.png" /> (A) inner balloon (B) outer balloon (C) both simultaneously (D) unpredictable

Tardigrade Admin · Accepted Answer

Using Charle's law (V1/T1)=(V2/T2) Sppose inner balloon burst first (600/300)=(800/T2) textT text2 = 400 textK At 400 textK the volume of outer balloon is text2000 textml so outer ballon burst first.

Q. Two inflated balloons I and II (thin skin) having volume 600 mL and 1500 mL at 300 K are taken as shown in diagram. If maximum volume of inner and outer balloons are 800 mL and 1800 mL respectively then find the balloon which will burst first on gradual heating.

inner balloon

outer balloon

both simultaneously

unpredictable

Using Charle's law

$\frac{V _{1}}{T _{1}} = \frac{V _{2}}{T _{2}}$

Sppose inner balloon burst first $\frac{600}{300} = \frac{800}{T _{2}}$

$T_{2} = 400 K$

At $400 K$ the volume of outer balloon is $2000 ml$ so outer ballon burst first.

Q. Two inflated balloons I and II (thin skin) having volume 600 mL and 1500 mL at 300 K are taken as shown in diagram. If maximum volume of inner and outer balloons are 800 mL and 1800 mL respectively then find the balloon which will burst first on gradual heating.

inner balloon

outer balloon

both simultaneously

unpredictable

Using Charle's law T1​V1​​=T2​V2​​ Sppose inner balloon burst first 300600​=T2​800​ T2​=400K At 400K the volume of outer balloon is 2000ml so outer ballon burst first.

Using Charle's law

$\frac{V _{1}}{T _{1}} = \frac{V _{2}}{T _{2}}$

Sppose inner balloon burst first $\frac{600}{300} = \frac{800}{T _{2}}$

$T_{2} = 400 K$

At $400 K$ the volume of outer balloon is $2000 ml$ so outer ballon burst first.