Two inductors each of inductance L are connected in parallel. Their equivalent inductance will be

Question

Two inductors each of inductance L are connected in parallel. Their equivalent inductance will be (A) zero (B)  (L/2)  (C)  2 L  (D)  L

Tardigrade Admin · Accepted Answer

Inductance of first inductor L1=L Inductance of second inductor L2=L Inductance connected in parallel, the equivalent inductance is given by (L/Lequi)=(L/L1)+(L/L2)=(L/L)+(L/L)=(2/L) Hence, Lequi=(L/2)

Q. Two inductors each of inductance $L$ are connected in parallel. Their equivalent inductance will be

zero

$\frac{L}{2}$

$2 L$

$L$

Inductance of first inductor $L_{1} = L$ Inductance of second inductor $L_{2} = L$ Inductance connected in parallel, the equivalent inductance is given by $\frac{L}{L _{e q u i}} = \frac{L}{L _{1}} + \frac{L}{L _{2}} = \frac{L}{L} + \frac{L}{L} = \frac{2}{L}$ Hence, $L_{e q u i} = \frac{L}{2}$

Q. Two inductors each of inductance L are connected in parallel. Their equivalent inductance will be

zero

2L​

2L

L

Inductance of first inductor L1​=L Inductance of second inductor L2​=L Inductance connected in parallel, the equivalent inductance is given by Lequi​L​=L1​L​+L2​L​=LL​+LL​=L2​ Hence, Lequi​=2L​

Q. Two inductors each of inductance $L$ are connected in parallel. Their equivalent inductance will be

$\frac{L}{2}$

$2 L$

$L$

Inductance of first inductor $L_{1} = L$ Inductance of second inductor $L_{2} = L$ Inductance connected in parallel, the equivalent inductance is given by $\frac{L}{L _{e q u i}} = \frac{L}{L _{1}} + \frac{L}{L _{2}} = \frac{L}{L} + \frac{L}{L} = \frac{2}{L}$ Hence, $L_{e q u i} = \frac{L}{2}$