Two identical thin bar magnets each of length l and pole strength m are placed at right angles to each other with north pole of one touching south pole of other, the magnetic moment of the system is

Question

Two identical thin bar magnets each of length l and pole strength m are placed at right angles to each other with north pole of one touching south pole of other, the magnetic moment of the system is (A) m l (B) 2 ml (C) √2 m l (D) m l / 2

Tardigrade Admin · Accepted Answer

Here, distance between two poles =√2 l Hence, M=m × √2 l=√2 m l

Q. Two identical thin bar magnets each of length $l$ and pole strength $m$ are placed at right angles to each other with north pole of one touching south pole of other, the magnetic moment of the system is

$m l$

$2 m l$

$2 m l$

$m l /2$

Here, distance between two poles $= 2 l$
Hence, $M = m \times 2 l = 2 m l$

Q. Two identical thin bar magnets each of length l and pole strength m are placed at right angles to each other with north pole of one touching south pole of other, the magnetic moment of the system is

ml

2ml

2​ml

ml/2

Here, distance between two poles =2​l Hence, M=m×2​l=2​ml

Q. Two identical thin bar magnets each of length $l$ and pole strength $m$ are placed at right angles to each other with north pole of one touching south pole of other, the magnetic moment of the system is

$m l$

$2 m l$

$2 m l$

$m l /2$

Here, distance between two poles $= 2 l$
Hence, $M = m \times 2 l = 2 m l$