Two identical particles are located at vecx and vecy with reference to the origin of three dimensional co-ordinate system. The position vector of centre of mass of the system is given by

Question

Two identical particles are located at vecx and vecy with reference to the origin of three dimensional co-ordinate system. The position vector of centre of mass of the system is given by (A)  vecx- vecy (B) ( vecx+ vecy/2) (C) ( vecx- vecy) (D) ( vecx- vecy/2)

Tardigrade Admin · Accepted Answer

vecr=(m1 vecr1+m2 vecr2/m1+m2)=(m( vecx+ vecy)/2 m)=( vecx+ vecy/2).

Q. Two identical particles are located at $x$ and $y$ with reference to the origin of three dimensional co-ordinate system. The position vector of centre of mass of the system is given by

$x - y$

$\frac{x + y}{2}$

$(x - y)$

$\frac{x - y}{2}$

$r = \frac{m _{1} r _{1} + m _{2} r _{2}}{m _{1} + m _{2}} = \frac{m ( x + y )}{2 m} = \frac{x + y}{2}$ .

Q. Two identical particles are located at x and y​ with reference to the origin of three dimensional co-ordinate system. The position vector of centre of mass of the system is given by

x−y​

2x+y​​

(x−y​)

2x−y​​