Two identical inductance carry currents that vary with time according to linear laws (as shown in figure). In which of two inductance is the selfinduction emf greater?

Question

Two identical inductance carry currents that vary with time according to linear laws (as shown in figure). In which of two inductance is the selfinduction emf greater? (A) 1 (B) 2 (C) same (D) data are insufficient to decide

Tardigrade Admin · Accepted Answer

ε=-L (d i/d t),-(d i/d t) is more for 1 ε=[(L(E / R)2/4(L / R))]=(E2/4 R)

Q. Two identical inductance carry currents that vary with time according to linear laws (as shown in figure). In which of two inductance is the selfinduction emf greater?

1

2

same

data are insufficient to decide

$ε = - L \frac{d i}{d t}, - \frac{d i}{d t}$ is more for $1$
$ε = [\frac{L ( E / R ) ^{2}}{4 ( L / R )}] = \frac{E ^{2}}{4 R}$

Q. Two identical inductance carry currents that vary with time according to linear laws (as shown in figure). In which of two inductance is the selfinduction emf greater?

1

2

same

data are insufficient to decide

ε=−Ldtdi​,−dtdi​ is more for 1 ε=[4(L/R)L(E/R)2​]=4RE2​

$ε = - L \frac{d i}{d t}, - \frac{d i}{d t}$ is more for $1$
$ε = [\frac{L ( E / R ) ^{2}}{4 ( L / R )}] = \frac{E ^{2}}{4 R}$