Two identical capacitors are joined in parallel and charged to a potential V. Then these are separated and connected in series with the positive plate of one connected to the negative of the other. Then the

Question

Two identical capacitors are joined in parallel and charged to a potential V. Then these are separated and connected in series with the positive plate of one connected to the negative of the other. Then the (A) potential difference between the plates becomes 2V (B) energy stored in the system increases (C) charges on the free plates are enhanced (D) charges on the plates connected together are destroyed

Tardigrade Admin · Accepted Answer

The potential of each capacitor is equal to V, when they are in parallel. If they are disconnected and joined in series, then the potential will become V'=V+V=2 V

Q. Two identical capacitors are joined in parallel and charged to a potential $V$ . Then these are separated and connected in series with the positive plate of one connected to the negative of the other. Then the

potential difference between the plates becomes 2V

energy stored in the system increases

charges on the free plates are enhanced

charges on the plates connected together are destroyed

The potential of each capacitor is equal to $V$ , when they are in parallel. If they are disconnected and joined in series, then the potential will become
$V^{'} = V + V = 2 V$

Q. Two identical capacitors are joined in parallel and charged to a potential V. Then these are separated and connected in series with the positive plate of one connected to the negative of the other. Then the