Two identical bodies are made of a material for which the heat capacity increases with temperature. One of these is at 100° C , while the other one is at 0° C. If the two bodies are brought into contact, then, assuming no heat loss, the final common temperature is -

Question

Two identical bodies are made of a material for which the heat capacity increases with temperature. One of these is at 100° C , while the other one is at 0° C. If the two bodies are brought into contact, then, assuming no heat loss, the final common temperature is - (A) 50° C (B) more than 50° C (C) less than 50° C but greater than 0° C (D) 0° C

Tardigrade Admin · Accepted Answer

Due to temperature heat capacity increase so heat capacity of second will greater than first.
Let heat capacity are

c_{1}

&

c_{2}

and common temperature

T

so

m c_{1} (T - 0) = m c_{2} (100 - T)

\frac{T}{100 - T} = \frac{c _{2}}{c _{1}} > 1 {c_{2} > c_{1}}

T > 50

Q. Two identical bodies are made of a material for which the heat capacity increases with temperature. One of these is at $10 0^{\circ} C$ , while the other one is at $0^{\circ} C$ . If the two bodies are brought into contact, then, assuming no heat loss, the final common temperature is -

$5 0^{\circ} C$

more than $5 0^{\circ} C$

less than $5 0^{\circ} C$ but greater than $0^{\circ} C$

$0^{\circ} C$

Due to temperature heat capacity increase so heat capacity of second will greater than first.
Let heat capacity are $c_{1}$ & $c_{2}$ and common temperature $T$
so $m c_{1} (T - 0) = m c_{2} (100 - T)$
$\frac{T}{100 - T} = \frac{c _{2}}{c _{1}} > 1 {c_{2} > c_{1}}$
$T > 50$

Q. Two identical bodies are made of a material for which the heat capacity increases with temperature. One of these is at 100∘C , while the other one is at 0∘C. If the two bodies are brought into contact, then, assuming no heat loss, the final common temperature is -

50∘C

more than 50∘C

less than 50∘C but greater than 0∘C

0∘C