Two gram of hydrogen diffuse from a container in 10 min. How many gram of oxygen would diffuse through the same container in the same time under similar conditions?

Question

Two gram of hydrogen diffuse from a container in 10 min. How many gram of oxygen would diffuse through the same container in the same time under similar conditions? (A) 0.5 g (B) 4 g (C) 6 g (D) 8 g

Tardigrade Admin · Accepted Answer

Rate of diffusion =(V/t) propto (1/√m) ⇒ (rH2/rO2) = (VH2/VO2) = (nH2/nO2) = √(MO2/MH2) (2/2/w/32) = √(32/2), (32/w) =4, w = 8 g

Q. Two gram of hydrogen diffuse from a container in $10$ min. How many gram of oxygen would diffuse through the same container in the same time under similar conditions?

0.5 g

4 g

6 g

8 g

Rate of diffusion $= \frac{V}{t} \propto \frac{1}{m}$
$\Rightarrow \frac{r _{H_{2}}}{r _{O_{2}}} = \frac{V _{H_{2}}}{V _{O_{2}}} = \frac{n _{H_{2}}}{n _{O_{2}}} = \frac{M _{O_{2}}}{M _{H_{2}}}$
$\frac{2/2}{w /32} = \frac{32}{2}, \frac{32}{w} = 4, w = 8 g$

Q. Two gram of hydrogen diffuse from a container in 10 min. How many gram of oxygen would diffuse through the same container in the same time under similar conditions?

0.5 g

4 g

6 g

8 g

Rate of diffusion =tV​∝m​1​ ⇒rO2​​rH2​​​=VO2​​VH2​​​=nO2​​nH2​​​=MH2​​MO2​​​​ w/322/2​=232​​,w32​=4,w=8g

Q. Two gram of hydrogen diffuse from a container in $10$ min. How many gram of oxygen would diffuse through the same container in the same time under similar conditions?

Rate of diffusion $= \frac{V}{t} \propto \frac{1}{m}$
$\Rightarrow \frac{r _{H_{2}}}{r _{O_{2}}} = \frac{V _{H_{2}}}{V _{O_{2}}} = \frac{n _{H_{2}}}{n _{O_{2}}} = \frac{M _{O_{2}}}{M _{H_{2}}}$
$\frac{2/2}{w /32} = \frac{32}{2}, \frac{32}{w} = 4, w = 8 g$