Two gases are at absolute temperatures 300 K and 350 K respectively. The ratio of average kinetic energy of their molecules is

Question

Two gases are at absolute temperatures 300 K and 350 K respectively. The ratio of average kinetic energy of their molecules is (A)  6:7  (B)  1:5  (C)  1:1  (D)  5:1

Tardigrade Admin · Accepted Answer

From the relation, overlineKE=(3/2)kT ⇒ (( overlineKE)1/( overlineKE)2)=(T1/T2) Given: T1=300K, T2=350K ⇒ (( overlineKE)1/( overlineKE)2)=(300/350)=(6/7)

Q. Two gases are at absolute temperatures 300 K and 350 K respectively. The ratio of average kinetic energy of their molecules is

$6 : 7$

$1 : 5$

$1 : 1$

$5 : 1$

From the relation, $\overline{K E} = \frac{3}{2} k T$ $\Rightarrow$ $\frac{( K E ) _{1}}{( K E ) _{2}} = \frac{T _{1}}{T _{2}}$ Given : $T_{1} = 300 K,$ $T_{2} = 350 K$ $\Rightarrow$ $\frac{( K E ) _{1}}{( K E ) _{2}} = \frac{300}{350} = \frac{6}{7}$