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Physics
Two gases are at absolute temperatures 300 K and 350 K respectively. The ratio of average kinetic energy of their molecules is
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Q. Two gases are at absolute temperatures 300 K and 350 K respectively. The ratio of average kinetic energy of their molecules is
CMC Medical
CMC Medical 2007
A
$ 6:7 $
B
$ 1:5 $
C
$ 1:1 $
D
$ 5:1 $
Solution:
From the relation, $ \overline{KE}=\frac{3}{2}kT $ $ \Rightarrow $ $ \frac{{{(\overline{KE})}_{1}}}{{{(\overline{KE})}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}} $ Given : $ {{T}_{1}}=300K,\, $ $ {{T}_{2}}=350K $ $ \Rightarrow $ $ \frac{{{(\overline{KE})}_{1}}}{{{(\overline{KE})}_{2}}}=\frac{300}{350}=\frac{6}{7} $