Two gases are at absolute temperatures 300 K and 350 K respectively. The ratio of average kinetic energy of their molecules is

Question

Two gases are at absolute temperatures 300 K and 350 K respectively. The ratio of average kinetic energy of their molecules is (A)  6:7  (B)  36:49  (C)  7:6  (D)  343:216

Tardigrade Admin · Accepted Answer

From the relation, overline KE =(3/2) k T ⇒ (( overline KE )1/( overline KE )2)=(T1/T2) (become k is constant) Given, T1=300 K, T2=350 K ∴ (( KE )1/( KE )2)=(300/350)=(6/7)

Q. Two gases are at absolute temperatures $300 K$ and $350 K$ respectively. The ratio of average kinetic energy of their molecules is

$6 : 7$

$36 : 49$

$7 : 6$

$343 : 216$

From the relation,
$\overline{K E} = \frac{3}{2} k T$
$\Rightarrow \frac{( K E ) _{1}}{( K E ) _{2}} = \frac{T _{1}}{T _{2}}$
(become $k$ is constant)
Given, $T_{1} = 300 K, T_{2} = 350 K$
$∴ \frac{( K E ) _{1}}{( K E ) _{2}} = \frac{300}{350} = \frac{6}{7}$

Q. Two gases are at absolute temperatures 300K and 350K respectively. The ratio of average kinetic energy of their molecules is

6:7

36:49

7:6

343:216