Two gases, ammonia and hydrogen chloride, are passed in a long glass tube from opposite ends. The white ring will be formed at:

Question

Two gases, ammonia and hydrogen chloride, are passed in a long glass tube from opposite ends. The white ring will be formed at: (A) nearer to HCl end (B) nearer to ammonia end (C) throughout the length of tube (D) at the centre of the tube.

Tardigrade Admin · Accepted Answer

Molecular w.t. of NH3=14+3=17 Molecular w.t. of HCl=35.5+1=36.5 According to Grahams law: r propto (1/√M) Hence, the rate of diffusion will be higher for ammonia as it is lighter than HCl. Hence, white ring of NH4Cl will be formed nearer to HCl end.

Q. Two gases, ammonia and hydrogen chloride, are passed in a long glass tube from opposite ends. The white ring will be formed at:

nearer to $H Cl$ end

nearer to ammonia end

throughout the length of tube

at the centre of the tube.

Molecular w.t. of $N H_{3} = 14 + 3 = 17$ Molecular w.t. of $H Cl = 35.5 + 1 = 36.5$ According to Grahams law: $r \propto \frac{1}{M}$ Hence, the rate of diffusion will be higher for ammonia as it is lighter than $H Cl .$ Hence, white ring of $N H_{4} Cl$ will be formed nearer to $H Cl$ end.