Question

Two gases A and B having the same temperature 'T', same pressure 'P' and same volume 'V' are mixed. If the temperature of mixture is unchanged and the volume occupied by it is 'V/2', then the pressure of the mixture will be

• A. P/2
• B. P
• C. 2P
• D. 4P

Answer 1

Answer: (D)

Since temperature, pressure and volume are same for both the gases implies that their number of moles, on mixing becomes double. Keeping the temperature same and reducing the volume to half, pressure becomes 4 times.

$P_1{V}_1=n_{1}RT$

$P_2.\frac{V_1}{2}=2n,RT$

That is $P_2=4P_1$