Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated?

Question

Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated? (A) 2 ! 3 ! 4 ! (B) (3 !)3 ⋅(4 !) (C) (3 !)2 ⋅(4 !) (D) 3 !(4 !)3

Tardigrade Admin · Accepted Answer

Correct answer is (b) (3 !)3 ⋅(4 !)

Q. Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated?

$2! 3! 4!$

$(3!)^{3} \cdot (4!)$

$(3!)^{2} \cdot (4!)$

$3! (4!)^{3}$

Correct answer is (b) $(3!)^{3} \cdot (4!)$

Q. Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated?

2!3!4!

(3!)3⋅(4!)

(3!)2⋅(4!)

3!(4!)3

Correct answer is (b) (3!)3⋅(4!)

$2! 3! 4!$

$(3!)^{3} \cdot (4!)$

$(3!)^{2} \cdot (4!)$

$3! (4!)^{3}$

Correct answer is (b) $(3!)^{3} \cdot (4!)$