Question

Two fair dice, each with faces numbered $1,2,3,4,5$ and $6$, are rolled together and the sum of the numbers on the faces is observed. This process is repeated till the sum is either a prime number or a perfect square. Suppose the sum turns out to be a perfect square before it turns out to be a prime number. If $p$ is the probability that this perfect square is an odd number, then the value of $14p$ is _____

Answer 1

Answer: 8.00

Sum is perfect square if die's show $\{(1,3)(3,1)(2,2)(3,6)(6,3)(4,5)(5,4)\}$
so probability sum is $9$ when it is perfect square $p=4/7$
$14p=8$