Two equal point masses are separated by a distance d1. The force of gravitation acting between them is F1. If the separation is decreased to d2, then the new force of gravitation F2 is given by

Question

Two equal point masses are separated by a distance d1. The force of gravitation acting between them is F1. If the separation is decreased to d2, then the new force of gravitation F2 is given by (A) F2=F1 (B) F2=F1((d1/d2))2 (C) F2=F1((d2/d1))2 (D) F2=F1((d1/d2))

Tardigrade Admin · Accepted Answer

From Newton's law of gravitation, the two equal point masses are separated by a distance d1 is shown below

Gravitational force, F1=(G m ⋅ m/d12)=(G m2/d12) ....(i) Similarly,

Gravitational force, F2=(G m2/d22) .... (ii) On dividing Eq. (i) by Eq. (ii), we get (F1/F2) =((d2/d1))2 ∴ F2 =F1((d1/d2))2

Q. Two equal point masses are separated by a distance $d_{1}$ . The force of gravitation acting between them is $F_{1}$ . If the separation is decreased to $d_{2}$ , then the new force of gravitation $F_{2}$ is given by

$F_{2} = F_{1}$

$F_{2} = F_{1} (\frac{d _{1}}{d _{2}})^{2}$

$F_{2} = F_{1} (\frac{d _{2}}{d _{1}})^{2}$

$F_{2} = F_{1} (\frac{d _{1}}{d _{2}})$

Q. Two equal point masses are separated by a distance d1​. The force of gravitation acting between them is F1​. If the separation is decreased to d2​, then the new force of gravitation F2​ is given by

F2​=F1​

F2​=F1​(d2​d1​​)2

F2​=F1​(d1​d2​​)2

F2​=F1​(d2​d1​​)

Q. Two equal point masses are separated by a distance $d_{1}$ . The force of gravitation acting between them is $F_{1}$ . If the separation is decreased to $d_{2}$ , then the new force of gravitation $F_{2}$ is given by

$F_{2} = F_{1}$

$F_{2} = F_{1} (\frac{d _{1}}{d _{2}})^{2}$

$F_{2} = F_{1} (\frac{d _{2}}{d _{1}})^{2}$

$F_{2} = F_{1} (\frac{d _{1}}{d _{2}})$