Two equal point charges each of 3 μ C are separated by a certain distance in metres. If they are located at ( hati+ hatj+ hatk) and (2 hati+3 hatj+ hatk) then the electrostatic force between them is

Question

Two equal point charges each of 3 μ C are separated by a certain distance in metres. If they are located at ( hati+ hatj+ hatk) and (2 hati+3 hatj+ hatk) then the electrostatic force between them is (A) 9 × 10-3 N (B) 16.2 × 10-3 N (C) 10-3 N (D) 9 × 10-2 N

Tardigrade Admin · Accepted Answer

The distance between two charges is r =√(2-1)2+(3-1)2+(1-1)2=√5 By Coulomb's law, the force between two charges is F =(1/4 π ϵ0) ( q 1 q 2/ r 2)=(9 × .109)((3 × 10-6 × 3 × 10-6/5))=16.2 × 10-3 N

Q. Two equal point charges each of $3 μ C$ are separated by a certain distance in metres. If they are located at $(\hat{i} + \hat{j} + \hat{k})$ and $(2 \hat{i} + 3 \hat{j} + \hat{k})$ then the electrostatic force between them is

$9 \times 1 0^{- 3} N$

$16.2 \times 1 0^{- 3} N$

$1 0^{- 3} N$

$9 \times 1 0^{- 2} N$

$3 \times 1 0^{- 3} N$

Q. Two equal point charges each of 3μC are separated by a certain distance in metres. If they are located at (i^+j^​+k^) and (2i^+3j^​+k^) then the electrostatic force between them is

9×10−3N

16.2×10−3N

10−3N

9×10−2N

3×10−3N