Two energy levels of an electron in an atom are separated by 2.3 eV . The frequency of radiation emitted when the electrons to go from higher to lower level is

Question

Two energy levels of an electron in an atom are separated by 2.3 eV . The frequency of radiation emitted when the electrons to go from higher to lower level is (A)  6.95 × 1014 Hz  (B)  3.68 × 1015 Hz  (C)  5.6 × 1014 Hz  (D)  9.11 × 1015 Hz

Tardigrade Admin · Accepted Answer

Given, E2-E1=2.3 eV or V=(E2-E1/h) =(2.3×1.6×10-19/6.6× 10-34) =0.55×1015 =5.5× 1014 HZ

Q. Two energy levels of an electron in an atom are separated by $2.3 e V$ . The frequency of radiation emitted when the electrons to go from higher to lower level is

$6.95 \times 1 0^{14} Hz$

$3.68 \times 1 0^{15} Hz$

$5.6 \times 1 0^{14} Hz$

$9.11 \times 1 0^{15} Hz$

Given, $E_{2} - E_{1} = 2.3 e V$
or $V = \frac{E _{2} - E _{1}}{h}$
$= \frac{2.3 \times 1.6 \times 1 0 ^{- 19}}{6.6 \times 1 0 ^{- 34}}$
$= 0.55 \times 1 0^{15}$
$= 5.5 \times 1 0^{14} H Z$

Q. Two energy levels of an electron in an atom are separated by 2.3eV . The frequency of radiation emitted when the electrons to go from higher to lower level is

6.95×1014Hz

3.68×1015Hz

5.6×1014Hz

9.11×1015Hz